(4x^2-3x-10)=(x-2)

Solution for (4x^2-3x-10)=(x-2) equation:

(4x^2-3x-10)=(x-2)

We move all terms to the left:

(4x^2-3x-10)-((x-2))=0

We get rid of parentheses

4x^2-3x-((x-2))-10=0


We calculate terms in parentheses: -((x-2)), so:

(x-2)

We get rid of parentheses

x-2

Back to the equation:

-(x-2)


We get rid of parentheses

4x^2-3x-x+2-10=0

We add all the numbers together, and all the variables

4x^2-4x-8=0

a = 4; b = -4; c = -8;
Δ = b2-4ac
Δ = -42-4·4·(-8)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-12}{2*4}=\frac{-8}{8}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+12}{2*4}=\frac{16}{8}
=2
$